作业 1010

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10/10 作业

Homework 8

  1. m2m \ne -2 or 11 , sol. = ((1m+2)m+1m+2m+1m+2)\begin{pmatrix}\mathop{-}\left( \frac{1}{m\mathop{+}2}\right) \\ \frac{m\mathop{+}1}{m\mathop{+}2}\\ \frac{m\mathop{+}1}{m\mathop{+}2}\end{pmatrix} .

  2. A=(321242123)A^* = \begin{pmatrix}3 & 2 & 1\\ 2 & 4 & 2\\ 1 & 2 & 3\end{pmatrix} , A1=(34121412112141234)A^{-1} = \begin{pmatrix}\frac{3}{4} & \frac{1}{2} & \frac{1}{4}\\ \frac{1}{2} & 1 & \frac{1}{2}\\ \frac{1}{4} & \frac{1}{2} & \frac{3}{4}\end{pmatrix} .

  3. A=(0001010000101000)A^* = \begin{pmatrix}0 & 0 & 0 & \mathop{-}1\\ 0 & \mathop{-}1 & 0 & 0\\ 0 & 0 & \mathop{-}1 & 0\\ \mathop{-}1 & 0 & 0 & 0\end{pmatrix} , B=(240000120000800006)B^* = \begin{pmatrix}24 & 0 & 0 & 0\\ 0 & 12 & 0 & 0\\ 0 & 0 & 8 & 0\\ 0 & 0 & 0 & 6\end{pmatrix} .

  4. (1) A2A|A|^2 A .

    (2) Inverse.

    (3) (AB)=BA(AB)^* = BA .

Optional

  1. (dx1,dy1,dp)=((R11)R2(α1)αde2R2αR1α+R1R2α(R1ααR1)de2R2αR1α+R1R1R2αde2(α1)(R2αR1α+R1))(dx_1, dy_1, dp) = \begin{pmatrix} - \frac{\left( {R_1}\mathop{-}1\right) {R_2} \left( \alpha\mathop{-}1\right) \alpha d {e_2}}{{R_2} \alpha\mathop{-}{R_1} \alpha\mathop{+}{R_1}}\\ -\frac{{R_2} \alpha \left( {R_1} \alpha\mathop{-}\alpha\mathop{-}{R_1}\right) d {e_2}}{{R_2} \alpha\mathop{-}{R_1} \alpha\mathop{+}{R_1}}\\ -\frac{{R_1} {R_2} \alpha d {e_2}}{\left( \alpha\mathop{-}1\right) \, \left( {R_2} \alpha\mathop{-}{R_1} \alpha\mathop{+}{R_1}\right) }\end{pmatrix} .

    If de2>0de_2 > 0 , then dy1>0dy_1 > 0 and dp>0dp > 0 .

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