作业 1028

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10/28 作业

Homework 12

  1. (1) {(1,1,1),(1,2,3)}\left\{ (1, 1, 1), (1, 2, 3) \right\} , {(−2,1,0)}\left\{ (-2, 1, 0) \right\} .

    (2) {(0,1),(1,0)}\left\{ (0, 1), (1, 0) \right\} , {(−2,1,0,0,0),(0,0,2,−5,3),(0,3,8,−2,0)}\left\{ (-2, 1, 0, 0, 0), (0, 0, 2, -5, 3), (0, 3, 8, -2, 0) \right\} .

    (3) {(1,0,0,0),(1,1,1,1),(1,2,3,4)}\left\{ (1, 0, 0, 0), (1, 1, 1, 1), (1, 2, 3, 4) \right\} , {(−3,−2,1,0)}\left\{ (-3, -2, 1, 0) \right\} .

    (4) {(−3,1,2),(−1,2,5)}\left\{ (-3, 1, 2), (-1, 2, 5) \right\} , {(−10,−5,0,0,0),(0,0,−20,15,5),(0,5,20,−10,0)}\left\{ (-10, -5, 0, 0, 0), (0, 0, -20, 15, 5), (0, 5, 20, -10, 0) \right\} .

    (5) {(−4,−3,2,5),(2,4,6,0),(5,7,9,−9)}\left\{ (-4, -3, 2, 5), (2, 4, 6, 0), (5, 7, 9, -9) \right\} , {(0,−22,−34,6,4),(4,−16,−24,0,0)}\left\{ (0, -22, -34, 6, 4), (4, -16, -24, 0, 0) \right\} .

  2. (a) No.

    (b) No.

    (c) Yes.

    (d) No.

  3. R−{29}\R - \left\{ 29 \right\} .

  4. {(1,2,0,0),(0,2,1,0),(0,4,0,1)}\left\{ (1, 2, 0, 0), (0, 2, 1, 0), (0, 4, 0, 1) \right\} .

  5. dim⁡V≥m−n\dim V \ge m - n .

    Proof Let AA be the coefficient matrix. Then dim⁡V=nullity⁡A\dim V = \operatorname{nullity} A . Since rank⁡A+nullity⁡A=m\operatorname{rank} A + \operatorname{nullity} A = m , and rank⁡A≤n\operatorname{rank} A \le n , we have dim⁡V≥m−n\dim V \ge m - n □\square .

  6. (1) LL .

    (2) XX .

    (3) HH , LL .

  7. (a) False.

    (b) False.

    (c) True.

    (d) False.

  8. a. Equal.

    b. Equal.

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